黑白點的匹配貪心算法 設平面上分布著n個白點和n個黑點，每個點用一對坐標（x, y）表示。一個黑點b=（xb,yb）支配一個白點w=(xw, yw)當且僅當xb>=xw和yb>=yw。若黑點b支配白點w，則黑點b和白點w可匹配（可形成一個匹配對）。在一個黑點最多只能與一個白點匹配，一個白點最多只能與一個黑點匹配的前提下，求n個白點和n個黑點的最大匹配對數。
上傳時間： 2015-10-25
上傳用戶：zhliu007
this document is about probabilistic database techniques and applications it is a good tutorial if you are interested in this area
標簽： probabilistic applications techniques document
上傳時間： 2013-12-29
上傳用戶：ddddddos
We have a group of N items (represented by integers from 1 to N), and we know that there is some total order defined for these items. You may assume that no two elements will be equal (for all a, b: a<b or b<a). However, it is expensive to compare two items. Your task is to make a number of comparisons, and then output the sorted order. The cost of determining if a < b is given by the bth integer of element a of costs (space delimited), which is the same as the ath integer of element b. Naturally, you will be judged on the total cost of the comparisons you make before outputting the sorted order. If your order is incorrect, you will receive a 0. Otherwise, your score will be opt/cost, where opt is the best cost anyone has achieved and cost is the total cost of the comparisons you make (so your score for a test case will be between 0 and 1). Your score for the problem will simply be the sum of your scores for the individual test cases.
標簽： represented integers group items
上傳時間： 2016-01-17
上傳用戶：jeffery
* first open client.cpp and search for that USER_MSG_INTERCEPT(TeamInfo) over it u add this Code: USER_MSG_INTERCEPT(Health) { BEGIN_READ(pbuf,iSize) me.iHealth = READ_BYTE() return USER_MSG_CALL(Health) } * then we search for int HookUserMsg (char *szMsgName, pfnUserMsgHook pfn) and add this Code: REDIRECT_MESSAGE( Health ) *k now we have the health registered and can read it out i stop this hear know cuz i must thanks panzer and w00t.nl that they helped me with it first time! *ok now we go to int HUD_Redraw (float x, int y) and packing this draw code in it Code:
標簽： USER_MSG_INTERCEPT TeamInfo client search
上傳時間： 2016-01-22
上傳用戶：ynzfm
％求輸入一維信號的計盒分形維數 ％y是一維信號 ％cellmax:方格子的最大邊長,可以取2的偶數次冪次(1,2,4,8...),取大于數據長度的偶數 ％D是y的計盒維數（一般情況下D>=1）,D=lim(log(N(e))/log(k/e)),
上傳時間： 2013-12-13
上傳用戶：671145514
（1）利用多項式擬合的兩個模塊程序求解下題： 給出 x、y的觀測值列表如下： x 0 1 2 3 4 5 y 2.08 7.68 13.8 27.1 40.8 61.2 試利用二次多項式y=a0+a1x+a2x2進行曲線擬合。 （1）多項式擬合方法：假設我們收集到兩個相關變量x、y的n對觀測值列表： x x0 x1 x2 x3 x4 x5 y y0 y1 y2 y3 y4 y5 我們希望用m+1個基函數w0(x),w1(x),…,wm(x)的一個線形組合 y=a0w0(x)+a1w1(x)+…+amwm(x) 來近似的表達x、y間的函數關系，我們把幾對測量值分別代入上式中，就可以得到一個線形方程組： a0w0(x0)+a1w1(x0)+…+amwm(x0)=y0 a0w0(x1)+a1w1(x1)+…+amwm(x1)=y1 … … a0w0(xn)+a1w1(xn)+…+amwm(xn)=yn 只需要求出該線形方程組的最小二乘解，就能得到所構造的的多項式的系數，從而解決問題。
上傳時間： 2016-02-07
上傳用戶：爺的氣質
n this demo, we show how to use Rao-Blackwellised particle filtering to exploit the conditional independence structure of a simple DBN. The derivation and details are presented in A Simple Tutorial on Rao-Blackwellised Particle Filtering for Dynamic Bayesian Networks. This detailed discussion of the ABC network should complement the UAI2000 paper by Arnaud Doucet, Nando de Freitas, Kevin Murphy and Stuart Russell. After downloading the file, type "tar -xf demorbpfdbn.tar" to uncompress it. This creates the directory webalgorithm containing the required m files. Go to this directory, load matlab5 and type "dbnrbpf" for the demo.
標簽： Rao-Blackwellised conditional filtering particle
上傳時間： 2013-12-17
上傳用戶：zhaiyanzhong
A new PLL topology and a new simplified linear model are presented. The new fractional-N synthesizer presents no reference spurs and lowers the overall phase noise, thanks to the presence of a SampleJHold block. With a new simulation methodology it is possible to perform very accurate simulations, whose results match closely those obtained with the linear PLL model developed.
標簽： new fractional-N synthesizer simplified
上傳時間： 2016-04-14
上傳用戶：hjshhyy
實現最優二叉樹的構造；在此基礎上完成哈夫曼編碼器與譯碼器。 假設報文中只會出現如下表所示的字符： 字符 A B C D E F G H I J K L M N 頻度 186 64 13 22 32 103 21 15 47 57 1 5 32 20 57 字符 O P Q R S T U V W X Y Z ， ． 頻度 63 15 1 48 51 80 23 8 18 1 16 1 6 2 要求完成的系統應具備如下的功能： 1．初始化。從終端（文件）讀入字符集的數據信息，。建立哈夫曼樹。 2．編碼：利用已建好的哈夫曼樹對明文文件進行編碼，并存入目標文件（哈夫曼碼文件）。 3．譯碼：利用已建好的哈夫曼樹對目標文件（哈夫曼碼文件）進行編碼，并存入指定的明文文件。 4．輸出哈夫曼編碼文件：輸出每一個字符的哈夫曼編碼。
上傳時間： 2014-11-23
上傳用戶：shanml
屬用者輸入一數字n，程式便會產生一個4n*4n的魔術方陣，魔術方陣除顯示於螢幕上並會產生一檔案magic.txt檔案中同樣會有魔術方陣
標簽：
上傳時間： 2016-06-10
上傳用戶：924484786
