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sed-on-Road-<b>netWork</b>

  • 1.有三根桿子A,B,C。A桿上有若干碟子 2.每次移動一塊碟子,小的只能疊在大的上面 3.把所有碟子從A桿全部移到C桿上 經過研究發現

    1.有三根桿子A,B,C。A桿上有若干碟子 2.每次移動一塊碟子,小的只能疊在大的上面 3.把所有碟子從A桿全部移到C桿上 經過研究發現,漢諾塔的破解很簡單,就是按照移動規則向一個方向移動金片: 如3階漢諾塔的移動:A→C,A→B,C→B,A→C,B→A,B→C,A→C 此外,漢諾塔問題也是程序設計中的經典遞歸問題

    標簽: 移動 發現

    上傳時間: 2016-07-25

    上傳用戶:gxrui1991

  • Isisns is an extension of Network Simulator (ns) for the IS-IS routing protocol. It is focused on si

    Isisns is an extension of Network Simulator (ns) for the IS-IS routing protocol. It is focused on simulation of network dynamics and convergence.

    標簽: Simulator extension protocol Network

    上傳時間: 2016-11-06

    上傳用戶:thesk123

  • 1. 下列說法正確的是 ( ) A. Java語言不區分大小寫 B. Java程序以類為基本單位 C. JVM為Java虛擬機JVM的英文縮寫 D. 運行Java程序需要先安裝JDK

    1. 下列說法正確的是 ( ) A. Java語言不區分大小寫 B. Java程序以類為基本單位 C. JVM為Java虛擬機JVM的英文縮寫 D. 運行Java程序需要先安裝JDK 2. 下列說法中錯誤的是 ( ) A. Java語言是編譯執行的 B. Java中使用了多進程技術 C. Java的單行注視以//開頭 D. Java語言具有很高的安全性 3. 下面不屬于Java語言特點的一項是( ) A. 安全性 B. 分布式 C. 移植性 D. 編譯執行 4. 下列語句中,正確的項是 ( ) A . int $e,a,b=10 B. char c,d=’a’ C. float e=0.0d D. double c=0.0f

    標簽: Java A. B. C.

    上傳時間: 2017-01-04

    上傳用戶:netwolf

  • 數字運算

    數字運算,判斷一個數是否接近素數 A Niven number is a number such that the sum of its digits divides itself. For example, 111 is a Niven number because the sum of its digits is 3, which divides 111. We can also specify a number in another base b, and a number in base b is a Niven number if the sum of its digits divides its value. Given b (2 <= b <= 10) and a number in base b, determine whether it is a Niven number or not. Input Each line of input contains the base b, followed by a string of digits representing a positive integer in that base. There are no leading zeroes. The input is terminated by a line consisting of 0 alone. Output For each case, print "yes" on a line if the given number is a Niven number, and "no" otherwise. Sample Input 10 111 2 110 10 123 6 1000 8 2314 0 Sample Output yes yes no yes no

    標簽: 數字 運算

    上傳時間: 2015-05-21

    上傳用戶:daguda

  • We have a group of N items (represented by integers from 1 to N), and we know that there is some tot

    We have a group of N items (represented by integers from 1 to N), and we know that there is some total order defined for these items. You may assume that no two elements will be equal (for all a, b: a<b or b<a). However, it is expensive to compare two items. Your task is to make a number of comparisons, and then output the sorted order. The cost of determining if a < b is given by the bth integer of element a of costs (space delimited), which is the same as the ath integer of element b. Naturally, you will be judged on the total cost of the comparisons you make before outputting the sorted order. If your order is incorrect, you will receive a 0. Otherwise, your score will be opt/cost, where opt is the best cost anyone has achieved and cost is the total cost of the comparisons you make (so your score for a test case will be between 0 and 1). Your score for the problem will simply be the sum of your scores for the individual test cases.

    標簽: represented integers group items

    上傳時間: 2016-01-17

    上傳用戶:jeffery

  • This article describes a sniffer for Windows. WinSniff is an application for capturing packets on th

    This article describes a sniffer for Windows. WinSniff is an application for capturing packets on the network. It displays all the packets that are transmitted on the local network and gives detailed information about each header in the packet. In order to keep it simple, I am not dealing with application level protocols. If you are interested, you can add features to support various application level protocols such as SMTP, FTP, NETBIOS etc

    標簽: application describes capturing for

    上傳時間: 2016-01-22

    上傳用戶:lijianyu172

  • The XML Toolbox converts MATLAB data types (such as double, char, struct, complex, sparse, logical)

    The XML Toolbox converts MATLAB data types (such as double, char, struct, complex, sparse, logical) of any level of nesting to XML format and vice versa. For example, >> project.name = MyProject >> project.id = 1234 >> project.param.a = 3.1415 >> project.param.b = 42 becomes with str=xml_format(project, off ) "<project> <name>MyProject</name> <id>1234</id> <param> <a>3.1415</a> <b>42</b> </param> </project>" On the other hand, if an XML string XStr is given, this can be converted easily to a MATLAB data type or structure V with the command V=xml_parse(XStr).

    標簽: converts Toolbox complex logical

    上傳時間: 2016-02-12

    上傳用戶:a673761058

  • CAN1.c and CAN2.c are a simple example of configuring a CAN network to transmit and receive data o

    CAN1.c and CAN2.c are a simple example of configuring a CAN network to transmit and receive data on a CAN network, and how to move information to and from CAN RAM message objects. Each C8051F040-TB CAN node is configured to send a message when it s P3.7 button is depressed/released, with a 0x11 to indicate the button is pushed, and 0x00 when released. Each node also has a message object configured to receive messages. The C8051 tests the received data and will turn on/off the target board s LED. When one target is loaded with CAN2.c and the other is loaded with CAN1.c, one target board s push-button will control the other target board s LED, establishing a simple control link via the CAN bus and can be observed directly on the target boards.

    標簽: CAN configuring and transmit

    上傳時間: 2013-12-11

    上傳用戶:weiwolkt

  • A byte comunication system made in java that can be used to send messages in betweeen computers on t

    A byte comunication system made in java that can be used to send messages in betweeen computers on the same network.

    標簽: comunication computers betweeen messages

    上傳時間: 2017-08-12

    上傳用戶:1159797854

  • 微電腦型數學演算式隔離傳送器

    特點: 精確度0.1%滿刻度 可作各式數學演算式功能如:A+B/A-B/AxB/A/B/A&B(Hi or Lo)/|A|/ 16 BIT類比輸出功能 輸入與輸出絕緣耐壓2仟伏特/1分鐘(input/output/power) 寬范圍交直流兩用電源設計 尺寸小,穩定性高

    標簽: 微電腦 數學演算 隔離傳送器

    上傳時間: 2014-12-23

    上傳用戶:ydd3625

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