/* * EULER S ALGORITHM 5.1 * * TO APPROXIMATE THE SOLUTION OF THE INITIAL VALUE PROBLEM: * Y = F(T,Y), A<=T<=B, Y(A) = ALPHA, * AT N+1 EQUALLY SPACED POINTS IN THE INTERVAL [A,B]. * * INPUT: ENDPOINTS A,B INITIAL CONDITION ALPHA INTEGER N. * * OUTPUT: APPROXIMATION W TO Y AT THE (N+1) VALUES OF T. */
標(biāo)簽： APPROXIMATE ALGORITHM THE SOLUTION
上傳時(shí)間： 2015-08-20
上傳用戶：zhangliming420
producer-consumer problem 的源碼
標(biāo)簽： producer-consumer problem 源碼
上傳時(shí)間： 2015-08-21
上傳用戶：llandlu
吃蘋果eating apple problem問題代碼
標(biāo)簽： problem eating apple 蘋果
上傳時(shí)間： 2015-08-21
上傳用戶：天涯
A free MS Word reader for Linux and RISC OS. Antiword converts the files from Word 2, 6, 7, 97, 2000 and 2002 to text and postscript. There are ports to BeOS, OS/2, MacOS X, VMS, DOS and others
標(biāo)簽： Word Antiword converts reader
上傳時(shí)間： 2015-08-22
上傳用戶：離殤
ACM試題An Easy Problem Description As we known, data stored in the computers is in binary form. The problem we discuss now is about the positive integers and its binary form. Given a positive integer I, you task is to find out an integer J, which is the minimum integer greater than I, and the number of 1 s in whose binary form is the same as that in the binary form of I. For example, if "78" is given, we can write out its binary form, "1001110". This binary form has 4 1 s. The minimum integer, which is greater than "1001110" and also contains 4 1 s, is "1010011", i.e. "83", so you should output "83".
標(biāo)簽： Description computers Problem binary
上傳時(shí)間： 2013-12-11
上傳用戶：libenshu01
ACM試題Problem K:Ones Description Given any integer 0 <= n <= 10000 not divisible by 2 or 5, some multiple of n is a number which in decimal notation is a sequence of 1 s. How many digits are in the smallest such a multiple of n?
標(biāo)簽： Description divisible Problem integer
上傳時(shí)間： 2015-08-23
上傳用戶：zhenyushaw
This a parallel genetic algorithm for a biinfomatics problem CSP
標(biāo)簽： biinfomatics algorithm parallel genetic
上傳時(shí)間： 2015-08-26
上傳用戶：x4587
Lamb problem: The analytical solution of vertical point source. This is very important for synthetic modeling
標(biāo)簽： analytical important synthetic solution
上傳時(shí)間： 2013-12-25
上傳用戶：hongmo
The problem with the IID_s is solved ! File-Structure: ~~~~~~~~~~~~~~~ DirectDraw.pas = DDraw.h + DVP.h (+ MultiMon.h) Direct3D.pas = D3D.h + D3DTypes.h + D3DCaps.h + D3DVec.inl + DXFile.h Direct3DRM.pas = D3DRM.h + D3DRMDef.h + D3DRMObj.h + D3DRMWin.h + RMXFGUID.h + RMXFTmpl.h DirectInput.pas = DInput.h (+ DinputD.h) DirectPlay.pas = DPlay.h + DPLobby.h DirectSound.pas = DSound.h DirectMusic.pas = DLS1.h + DLS2.h + DMDLS.h + DMError.h + DMKSCtrl.h + DMusicC.h + DMusicF.h + DMusicI.h + DMusBuff.h DirectSetup.pas = DSetup.h No Unit = dxsdk.inc
標(biāo)簽： File-Structure DirectDraw problem solved
上傳時(shí)間： 2015-09-04
上傳用戶：kikye
請(qǐng)下載方正Apabi Reader進(jìn)行閱讀。http://www.skycn.com/soft/5531.html
標(biāo)簽： Reader Apabi skycn 5531
上傳時(shí)間： 2015-09-05
上傳用戶：czl10052678
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