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  • 這個設計是使用Virtex-4實現DDR的控制器的

    這個設計是使用Virtex-4實現DDR的控制器的,設計分為三個主要模塊:Front-End FIFOs,DDR SDRAM Controller和Datapath Module。其中主要是DDR SDRAM Controller,當然還有測試模塊。

    標簽: Virtex DDR 控制器

    上傳時間: 2017-05-20

    上傳用戶:llandlu

  • Emdros is a text database middleware-layer aimed at storage and retrieval of "text plus information

    Emdros is a text database middleware-layer aimed at storage and retrieval of "text plus information about that text." This information could be linguistic analyses or other annotations. Emdros provides an abstraction of text that makes it well suited to storing /syntactic analyses/ of text, but other linguistic information is supported as well. Emdros comes with a query-language, MQL, that enables powerful queries. Emdros acts as a middleware-layer between a client (not provided) and a database back-end. Currently, PostgreSQL, MySQL, and SQLite (2 and 3) are supported, but other back-ends can easily be added.

    標簽: text middleware-layer information retrieval

    上傳時間: 2014-01-02

    上傳用戶:wfeel

  • Wireless range extenders or wireless repeaters can extend the range of an existing wireless network.

    Wireless range extenders or wireless repeaters can extend the range of an existing wireless network. Range extenders can be strategically placed to elongate a signal area or allow for the signal area to reach around barriers such as those created in L-shaped corridors. Wireless devices connected through repeaters will suffer from an increased latency for each hop. Additionally, a wireless device connected to any of the repeaters in the chain will have a throughput that is limited by the weakest link between the two nodes in the chain from which the connection originates to where the connection ends

    標簽: wireless range extenders repeaters

    上傳時間: 2014-01-02

    上傳用戶:zhangyigenius

  • AVR single-chip developed by a very low threshold, as long as the computer will be able to study the

    AVR single-chip developed by a very low threshold, as long as the computer will be able to study the development of AVR microcontroller. Only a single-chip ISP download beginners line, the editing, debugging of software programs through a direct line into the AVR microcontroller, which can develop AVR Series Single-chip package of a variety of devices. AVR single-chip microcomputer in the industry known as "front-line struggle to seize state power."

    標簽: single-chip developed threshold the

    上傳時間: 2017-09-12

    上傳用戶:shinesyh

  • AVR single-chip developed by a very low threshold, as long as the computer will be able to study the

    AVR single-chip developed by a very low threshold, as long as the computer will be able to study the development of AVR microcontroller. Only a single-chip ISP download beginners line, the editing, debugging of software programs through a direct line into the AVR microcontroller, which can develop AVR Series Single-chip package of a variety of devices. AVR single-chip microcomputer in the industry known as "front-line struggle to seize state power."

    標簽: single-chip developed threshold the

    上傳時間: 2013-12-09

    上傳用戶:invtnewer

  • 16進制轉十進制

    DATAS SEGMENT w dw 0 keybuf db 255      db 0      db 255 dup(0)      ;定義鍵盤輸入需要的緩沖區 DATAS ENDS STACKS SEGMENT db 200 dup(?) STACKS ENDS CODES SEGMENT ASSUME CS:CODES,DS:DATAS,SS:STACKS START: MOV AX,DATAS MOV DS,AX mov dx,offset keybuf     ;用0a號功能,輸入一個字符串 mov ah,0ah               ;用回車結束 int 21h mov dl,0ah               ;再進行換行,以便在下一行顯示轉換后的字符串  mov ah,2     int 21h ;  push ax ;   push dx ;      mov dl,cl ;     mov ah,02 ;     int 21h   ;   pop dx ;  pop ax mov bx,offset keybuf+1   ;取出字符串的字符個數,作為循環的次數 mov cl,[bx] mov ch,0     mov ax,0             again:  inc bx mov ax,[w] push bx mov bx,16 mul bx pop bx            ;是小寫字母,則轉換為大寫字母 mov [w],ax mov dl,[bx]             ;取出一個字符, cmp dl,'9' jbe lab1 cmp dl,'F' jbe lab2 sub dl,32 lab2: sub dl ,07h lab1:  sub dl,30h add [w],dx  loop again   mov ax,[w]  mov bx,-1 push bx mov bx,10 lab3 :mov dx,0 div bx  push dx cmp ax,0 jnz lab3 lab5: pop dx cmp dx,-1 jz lab4 add dl,30h mov ah,02 int 21h        jmp  lab5            ;循環,處理完整個字符串 lab4:  MOV AH,4CH INT 21H CODES ENDS END START

    標簽: 匯編

    上傳時間: 2015-04-02

    上傳用戶:wcc0310

  • 5.1功放全套方案PT2258

    UNTER EQU 35H;顯示計數 REMVOL  EQU  36H;音量連續控制 DISPBUFF1 EQU 37H; DISPBUFF2 EQU 38H; DISPBUFF3 EQU 39H; DISPBUFF EQU 3AH; SDA BIT P3.4 SCL BIT P3.2 MTD EQU 30H;PT2258數據首址 NUMBYT EQU 3BH;PT2258數據位數 CS_X1 EQU 3CH;遙控 CS0_X1 EQU 3DH U0_X1 EQU 3EH;遙控數據暫存區 NO_M EQU 40H;數據碼 FRONT EQU 41H

    標簽: PT2258

    上傳時間: 2015-04-26

    上傳用戶:solomon33

  • 判斷奇數或偶數

    判斷奇偶數的匯編程序CODE     SEGMENT          ASSUME   CS: CODE START:   MOV      AH,  01H         ; 調用 DOS中斷的1號子功能(鍵入一個字符),          INT      21H              ; AL←鍵入一位數字          CMP   AL,  30H    ; 若輸入比‘0’小的字符則重新輸入   JB   START   CMP   AL,  39H    ; 若輸入比‘9’大的字符則重新輸入   JA   START    CLC                       ; CF標志清0          SHR      AL,  1           ; AL最低位移入CF          JNC      EVN              ; 根據CF的狀態,判斷輸入數字的奇偶性          MOV      BL,  31H         ; 奇數,BL←1的ASCII碼          JMP      DISP EVN:     MOV      BL,  30H         ; 偶數,BL←0的ASCII碼 DISP:    MOV      AH,  02H         ; 調用DOS中斷的2號子功能,輸出字符          MOV      DL,  0AH         ; 輸出換行          INT      21H          MOV      DL,  0DH         ; 輸出回車          INT      21H          MOV      DL,  BL          ; 輸出標志字符          INT      21H   mov   ah, 1   int   21h          MOV      AH, 4CH          ; 返回DOS          INT      21H CODE     ENDS          END      START

    標簽:

    上傳時間: 2015-06-10

    上傳用戶:zhuangxj618

  • ggggif

    gif捕捉制作工具: Demo ends:1034044285 名字:kukuasir 注冊碼:這里輸入新注冊碼 錄制區域:0,0 1024x738 幀的延時:500 幀間透明:是 記錄時間信息:是 循環:是 屏幕仿真:是 覆蓋邊緣:是 覆蓋指針:是 Explorer 2.0 兼容:否 錄制尺寸:100

    標簽: gif捕捉制作

    上傳時間: 2015-10-19

    上傳用戶:dumpsoft

  • 數據結構實驗

    #include <iostream> #include <stdio.head> #include <stdlib.head> #include <string.head> #define ElemType int #define max 100 using namespace std; typedef struct node1 { ElemType data; struct node1 *next; }Node1,*LinkList;//鏈棧 typedef struct { ElemType *base; int top; }SqStack;//順序棧 typedef struct node2 { ElemType data; struct node2 *next; }Node2,*LinkQueue; typedef struct node22 { LinkQueue front; LinkQueue rear; }*LinkList;//鏈隊列 typedef struct { ElemType *base; int front,rear; }SqQueue;//順序隊列 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 //1.采用鏈式存儲實現棧的初始化、入棧、出棧操作。 LinkList CreateStack()//創建棧 { LinkList top; top=NULL; return top; } bool StackEmpty(LinkList s)//判斷棧是否為空,0代表空 { if(s==NULL) return 0; else return 1; } LinkList Pushead(LinkList s,int x)//入棧 { LinkList q,top=s; q=(LinkList)malloc(sizeof(Node1)); q->data=x; q->next=top; top=q; return top; } LinkList Pop(LinkList s,int &e)//出棧 { if(!StackEmpty(s)) { printf("棧為空。"); } else { e=s->data; LinkList p=s; s=s->next; free(p); } return s; } void DisplayStack(LinkList s)//遍歷輸出棧中元素 { if(!StackEmpty(s)) printf("棧為空。"); else { wheadile(s!=NULL) { cout<<s->data<<" "; s=s->next; } cout<<endl; } } 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 //2.采用順序存儲實現棧的初始化、入棧、出棧操作。 int StackEmpty(int t)//判斷棧S是否為空 { SqStack.top=t; if (SqStack.top==0) return 0; else return 1; } int InitStack() { SqStack.top=0; return SqStack.top; } int pushead(int t,int e) { SqStack.top=t; SqStack.base[++SqStack.top]=e; return SqStack.top; } int pop(int t,int *e)//出棧 { SqStack.top=t; if(!StackEmpty(SqStack.top)) { printf("棧為空."); return SqStack.top; } *e=SqStack.base[s.top]; SqStack.top--; return SqStack.top; } 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 //3.采用鏈式存儲實現隊列的初始化、入隊、出隊操作。 LinkList InitQueue()//創建 { LinkList head; head->rear=(LinkQueue)malloc(sizeof(Node)); head->front=head->rear; head->front->next=NULL; return head; } void deleteEle(LinkList head,int &e)//出隊 { LinkQueue p; p=head->front->next; e=p->data; head->front->next=p->next; if(head->rear==p) head->rear=head->front; free(p); } void EnQueue(LinkList head,int e)//入隊 { LinkQueue p=(LinkQueue)malloc(sizeof(Node)); p->data=e; p->next=NULL; head->rear->next=p; head->rear=p; } 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 //4.采用順序存儲實現循環隊列的初始化、入隊、出隊操作。 bool InitQueue(SqQueue &head)//創建隊列 { head.data=(int *)malloc(sizeof(int)); head.front=head.rear=0; return 1; } bool EnQueue(SqQueue &head,int e)//入隊 { if((head.rear+1)%MAXQSIZE==head.front) { printf("隊列已滿\n"); return 0; } head.data[head.rear]=e; head.rear=(head.rear+1)%MAXQSIZE; return 1; } int QueueLengthead(SqQueue &head)//返回隊列長度 { return (head.rear-head.front+MAXQSIZE)%MAXQSIZE; } bool deleteEle(SqQueue &head,int &e)//出隊 { if(head.front==head.rear) { cout<<"隊列為空!"<<endl; return 0; } e=head.data[head.front]; head.front=(head.front+1)%MAXQSIZE; return 1; } int gethead(SqQueue head)//得到隊列頭元素 { return head.data[head.front]; } int QueueEmpty(SqQueue head)//判斷隊列是否為空 { if (head.front==head.rear) return 1; else return 0; } void travelQueue(SqQueue head)//遍歷輸出 { wheadile(head.front!=head.rear) { printf("%d ",head.data[head.front]); head.front=(head.front+1)%MAXQSIZE; } cout<<endl; } 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 //5.在主函數中設計一個簡單的菜單,分別測試上述算法。 int main() { LinkList top=CreateStack(); int x; wheadile(scanf("%d",&x)!=-1) { top=Pushead(top,x); } int e; wheadile(StackEmpty(top)) { top=Pop(top,e); printf("%d ",e); }//以上是鏈棧的測試 int top=InitStack(); int x; wheadile(cin>>x) top=pushead(top,x); int e; wheadile(StackEmpty(top)) { top=pop(top,&e); printf("%d ",e); }//以上是順序棧的測試 LinkList Q; Q=InitQueue(); int x; wheadile(scanf("%d",&x)!=-1) { EnQueue(Q,x); } int e; wheadile(Q) { deleteEle(Q,e); printf("%d ",e); }//以上是鏈隊列的測試 SqQueue Q1; InitQueue(Q1); int x; wheadile(scanf("%d",&x)!=-1) { EnQueue(Q1,x); } int e; wheadile(QueueEmpty(Q1)) { deleteEle(Q1,e); printf("%d ",e); } return 0; }

    標簽: 數據結構 實驗

    上傳時間: 2018-05-09

    上傳用戶:123456..

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