ICTCLAS的JNI調用接口文件: Title:ICTCLAS Caller * <p>Description:do chinese word segmentation.don t change the pakage and CLASS name, orelse you can t use it. * 請不要改變包名、類名以及native的方法名，否則調用將失效。 * 由于ICTCLAS本身存在很多魯棒性問題，調用segSentence時，string參數請保證不要過長或帶有亂碼。調用次數過多（如處理幾十G的數據）會有可能造成內存溢出。 * 故基本只能用于較小規模數據（相對幾十G來說）。 * 請運行時設置jvm足夠的堆?？臻g。
標簽： ICTCLAS segmentation Description chinese
上傳時間： 2014-01-25
上傳用戶：it男一枚
See Appendix B for a Description of the programs included on this companion disk. RESOURCE.WRI identifies other books and resources for Internet programming. WEBHELP.HLP contains an introduction to the World Wide Web. TCPMAN.HLP provides detailed instructions to help you use the Trumpet Winsock included on this disk. Use the Program Manager s File menu Run option to execute the SETUP.EXE program found on this disk. SETUP.EXE will install the programs on your hard drive and create an Internet Programming group window. Internet編程技術 [配套程序] [涉及平臺] VC [作者] void [文件大小] 1032K
標簽： Description companion Appendix RESOURCE
上傳時間： 2013-12-04
上傳用戶：asasasas
This Verilog HDL Description implements a UART.
標簽： Description implements Verilog This
上傳時間： 2013-12-17
上傳用戶：wff
Details Description of Free BSD network source code.Those documents have explained each line of code.
標簽： code Description documents explained
上傳時間： 2015-07-01
上傳用戶：fandeshun
CML2 Language and Tools Description(EN).rar
標簽： Description Language Tools CML2
上傳時間： 2015-08-06
上傳用戶：netwolf
PCB Language and Tools Description(EN).rar
標簽： Description Language Tools PCB
上傳時間： 2013-12-23
上傳用戶：氣溫達上千萬的
CML2 Language and Tools Description(EN).rar
標簽： Description Language Tools CML2
上傳時間： 2013-11-30
上傳用戶：gyq
Name:neural Network Control, for Matlab,tipical Description for control problems with NN method, additionally, there are some useful examples to be referenced.
標簽： Description for problems Control
上傳時間： 2015-08-15
上傳用戶：siguazgb
ACM試題An Easy Problem Description As we known, data stored in the computers is in binary form. The problem we discuss now is about the positive integers and its binary form. Given a positive integer I, you task is to find out an integer J, which is the minimum integer greater than I, and the number of 1 s in whose binary form is the same as that in the binary form of I. For example, if "78" is given, we can write out its binary form, "1001110". This binary form has 4 1 s. The minimum integer, which is greater than "1001110" and also contains 4 1 s, is "1010011", i.e. "83", so you should output "83".
標簽： Description computers Problem binary
上傳時間： 2013-12-11
上傳用戶：libenshu01
ACM試題Problem K:Ones Description Given any integer 0 <= n <= 10000 not divisible by 2 or 5, some multiple of n is a number which in decimal notation is a sequence of 1 s. How many digits are in the smallest such a multiple of n?
標簽： Description divisible Problem integer
上傳時間： 2015-08-23
上傳用戶：zhenyushaw
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