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A<b>bode</b>P

  • prolog 找路例子程序: === === === === === === Part 1-Adding connections Part 2-Simple Path example

    prolog 找路例子程序: === === === === === === Part 1-Adding connections Part 2-Simple Path example | ?- path1(a,b,P,T). will produce the response: T = 15 P = [a,b] ? Part 3 - Non-repeating path As an example, the query: ?- path2(a,h,P,T). will succeed and may produce the bindings: P = [a,depot,b,d,e,f,h] T = 155 Part 4 - Generating a path below a cost threshold As an example, the query: ?- path_below_cost(a,[a,b,c,d,e,f,g,h],RS,300). returns: RS = [a,b,depot,c,d,e,g,f,h] ? RS = [a,c,depot,b,d,e,g,f,h] ? no ==================================

    標簽: Part connections example prolog

    上傳時間: 2015-04-24

    上傳用戶:ljt101007

  • 源代碼用動態規劃算法計算序列關系個數 用關系"<"和"="將3個數a

    源代碼\用動態規劃算法計算序列關系個數 用關系"<"和"="將3個數a,b,c依次序排列時,有13種不同的序列關系: a=b=c,a=b<c,a<b=v,a<b<c,a<c<b a=c<b,b<a=c,b<a<c,b<c<a,b=c<a c<a=b,c<a<b,c<b<a 若要將n個數依序列,設計一個動態規劃算法,計算出有多少種不同的序列關系, 要求算法只占用O(n),只耗時O(n*n).

    標簽: lt 源代碼 動態規劃 序列

    上傳時間: 2013-12-26

    上傳用戶:siguazgb

  • The government of a small but important country has decided that the alphabet needs to be streamline

    The government of a small but important country has decided that the alphabet needs to be streamlined and reordered. Uppercase letters will be eliminated. They will issue a royal decree in the form of a String of B and A characters. The first character in the decree specifies whether a must come ( B )Before b in the new alphabet or ( A )After b . The second character determines the relative placement of b and c , etc. So, for example, "BAA" means that a must come Before b , b must come After c , and c must come After d . Any letters beyond these requirements are to be excluded, so if the decree specifies k comparisons then the new alphabet will contain the first k+1 lowercase letters of the current alphabet. Create a class Alphabet that contains the method choices that takes the decree as input and returns the number of possible new alphabets that conform to the decree. If more than 1,000,000,000 are possible, return -1. Definition

    標簽: government streamline important alphabet

    上傳時間: 2015-06-09

    上傳用戶:weixiao99

  • 一:需求分析 1. 問題描述 魔王總是使用自己的一種非常精練而抽象的語言講話,沒人能聽懂,但他的語言是可逐步解釋成人能聽懂的語言,因為他的語言是由以下兩種形式的規則由人的語言逐步抽象上去的: -

    一:需求分析 1. 問題描述 魔王總是使用自己的一種非常精練而抽象的語言講話,沒人能聽懂,但他的語言是可逐步解釋成人能聽懂的語言,因為他的語言是由以下兩種形式的規則由人的語言逐步抽象上去的: ----------------------------------------------------------- (1) a---> (B1)(B2)....(Bm) (2)[(op1)(p2)...(pn)]---->[o(pn)][o(p(n-1))].....[o(p1)o] ----------------------------------------------------------- 在這兩種形式中,從左到右均表示解釋.試寫一個魔王語言的解釋系統,把 他的話解釋成人能聽得懂的話. 2. 基本要求: 用下述兩條具體規則和上述規則形式(2)實現.設大寫字母表示魔王語言的詞匯 小寫字母表示人的語言的詞匯 希臘字母表示可以用大寫字母或小寫字母代換的變量.魔王語言可含人的詞匯. (1) B --> tAdA (2) A --> sae 3. 測試數據: B(ehnxgz)B 解釋成 tsaedsaeezegexenehetsaedsae若將小寫字母與漢字建立下表所示的對應關系,則魔王說的話是:"天上一只鵝地上一只鵝鵝追鵝趕鵝下鵝蛋鵝恨鵝天上一只鵝地上一只鵝". | t | d | s | a | e | z | g | x | n | h | | 天 | 地 | 上 | 一只| 鵝 | 追 | 趕 | 下 | 蛋 | 恨 |

    標簽: 語言 抽象

    上傳時間: 2014-12-02

    上傳用戶:jkhjkh1982

  • We have a group of N items (represented by integers from 1 to N), and we know that there is some tot

    We have a group of N items (represented by integers from 1 to N), and we know that there is some total order defined for these items. You may assume that no two elements will be equal (for all a, b: a<b or b<a). However, it is expensive to compare two items. Your task is to make a number of comparisons, and then output the sorted order. The cost of determining if a < b is given by the bth integer of element a of costs (space delimited), which is the same as the ath integer of element b. Naturally, you will be judged on the total cost of the comparisons you make before outputting the sorted order. If your order is incorrect, you will receive a 0. Otherwise, your score will be opt/cost, where opt is the best cost anyone has achieved and cost is the total cost of the comparisons you make (so your score for a test case will be between 0 and 1). Your score for the problem will simply be the sum of your scores for the individual test cases.

    標簽: represented integers group items

    上傳時間: 2016-01-17

    上傳用戶:jeffery

  • 單純形法算法,int K,M,N,Q=100,Type,Get,Let,Et,Code[50],XB[50],IA,IAA[50],Indexg,Indexl,Indexe float Sum,A

    單純形法算法,int K,M,N,Q=100,Type,Get,Let,Et,Code[50],XB[50],IA,IAA[50],Indexg,Indexl,Indexe float Sum,A[50][50],B[50],C[50]

    標簽: 50 Indexg Indexe Indexl

    上傳時間: 2013-12-22

    上傳用戶:頂得柱

  • The "GEE! It s Simple" package illustrates Gaussian elimination with partial pivoting, which produce

    The "GEE! It s Simple" package illustrates Gaussian elimination with partial pivoting, which produces a factorization of P*A into the product L*U where P is a permutation matrix, and L and U are lower and upper triangular, respectively. The functions in this package are accurate, but they are far slower than their MATLAB equivalents (x=A\b, [L,U,p]=lu(A), and so on). They are presented here merely to illustrate and educate. "Real" production code should use backslash and lu, not this package.

    標簽: illustrates elimination Gaussian pivoting

    上傳時間: 2016-11-09

    上傳用戶:wang5829

  • The "GEE! It s Simple" package illustrates Gaussian elimination with partial pivoting, which produce

    The "GEE! It s Simple" package illustrates Gaussian elimination with partial pivoting, which produces a factorization of P*A into the product L*U where P is a permutation matrix, and L and U are lower and upper triangular, respectively. The functions in this package are accurate, but they are far slower than their MATLAB equivalents (x=A\b, [L,U,p]=lu(A), and so on). They are presented here merely to illustrate and educate. "Real" production code should use backslash and lu, not this package.

    標簽: illustrates elimination Gaussian pivoting

    上傳時間: 2014-01-21

    上傳用戶:lxm

  • made by: kangkai data:2008.11.23 this one is used to test arm7 str71x. use a led to test

    made by: kangkai data:2008.11.23 this one is used to test arm7 str71x. use a led to test GPIO. a---------P0.0 b---------P0.1 c---------P0.2 d---------P0.3 e---------P0.4 f---------P0.5 g---------P0.6 just run it and you will see the led to show 0-9 all the time.

    標簽: test kangkai made 2008

    上傳時間: 2016-12-16

    上傳用戶:moerwang

  • 12345

    /****************temic*********t5557***********************************/    #include   <at892051.h>     #include   <string.h>    #include   <intrins.h>     #include   <stdio.h>     #define    uchar    unsigned char     #define    uint     unsigned int     #define    ulong    unsigned long     //STC12C2051AD的SFR定義     sfr  WDT_CONTR = 0xe1;//stc2051的看門狗??????     /**********全局常量************/    //寫卡的命令     #define    write_command0       0//寫密碼     #define    write_command1       1//寫配置字     #define    write_command2       2//密碼寫數據     #define    write_command3       3//喚醒     #define    write_command4       4//停止命令     #define    TRUE       1     #define    FALSE      0     #define    OK         0     #define    ERROR      255     //讀卡的時間參數us     #define ts_min          250//270*11.0592/12=249//取近似的整數     #define ts_max          304//330*11.0592/12=304     #define t1_min          73//90*11.0592/12=83:-10調整     #define t1_max          156//180*11.0592/12=166     #define t2_min          184//210*11.0592/12=194     #define t2_max          267//300*11.0592/12=276     //***********不采用中斷處理:采用查詢的方法讀卡時關所有中斷****************/     sbit p_U2270B_Standby = P3^5;//p_U2270B_Standby PIN=13     sbit p_U2270B_CFE = P3^3;//p_U2270B_CFE     PIN=6     sbit p_U2270B_OutPut = P3^7;//p_U2270B_OutPut  PIN=2     sbit wtd_sck = P1^7;//SPI總線     sbit wtd_si = P1^3;    sbit wtd_so = P1^2;    sbit iic_data = P1^2;//lcd IIC     sbit iic_clk = P1^7;    sbit led_light = P1^6;//測試綠燈     sbit led_light1 = P1^5;//測試紅燈     sbit led_light_ok  = P1^1;//讀卡成功標志     sbit fengmingqi = P1^5;    /***********全局變量************************************/       uchar data Nkey_a[4] = {0xA0, 0xA1, 0xA2, 0xA3};//初始密碼             //uchar idata card_snr[4];   //配置字     uchar data bankdata[28] = {1,2,3,4,5,6,7,1,2,3,4,5,6,7,1,2,3,4,5,6,7,1,2,3,4,5,6,7};     //存儲卡上用戶數據(1-7)7*4=28     uchar data cominceptbuff[6] = {1,2,3,4,5,6};//串口接收數組ram     uchar command; //第一個命令     uchar command1;//     //uint  temp;     uchar j,i;    uchar myaddr = 8;    //uchar ywqz_count,time_count;             //ywqz jishu:     uchar bdata DATA;    sbit BIT0 = DATA^0;    sbit BIT1 = DATA^1;    sbit BIT2 = DATA^2;    sbit BIT3 = DATA^3;    sbit BIT4 = DATA^4;    sbit BIT5 = DATA^5;    sbit BIT6 = DATA^6;    sbit BIT7 = DATA^7;    uchar bdata DATA1;    sbit BIT10 = DATA1^0;    sbit BIT11 = DATA1^1;    sbit BIT12 = DATA1^2;    sbit BIT13 = DATA1^3;    sbit BIT14 = DATA1^4;    sbit BIT15 = DATA1^5;    sbit BIT16 = DATA1^6;    sbit BIT17 = DATA1^7;    bit i_CurrentLevel;//i_CurrentLevel  BIT 00H(Saves current level of OutPut pin of U2270B)     bit timer1_end;    bit read_ok = 0;    //緩存定時值,因用同一個定時器     union HLint { uint W;    struct   {    uchar H;uchar L;   }   B; };//union HLint idata a     union HLint data a;    //緩存定時值,因用同一個定時器     union HLint0 { uint W;    struct {   uchar H;   uchar L; } B; };//union HLint idata a     union HLint0 data b;    /**********************函數原型*****************/    //讀寫操作     void f_readcard(void);//全部讀出1~7 AOR喚醒     void f_writecard(uchar x);//根據命令寫不同的內容和操作     void f_clearpassword(void);//清除密碼     void f_changepassword(void);//修改密碼     //功能子函數     void write_password(uchar data *data p);//寫初始密碼或數據     void write_block(uchar x,uchar data *data p);//不能用通用指針     void write_bit(bit x);//寫位     /*子函數區*****************************************************/    void delay_2(uint x)    //延時,時間x*10us@12mhz,最小20us@12mhz     {    x--; x--;    while(x)    {      _nop_();      _nop_();      x--;    }    _nop_();//WDT_CONTR=0X3C;不能頻繁的復位     _nop_();    }    /////////////////////////////////////////////////////////////////////     void initial(void)    {    SCON = 0x50; //串口方式1,允許接收     //SCON  =0x50;     //01010000B:10位異步收發,波特率可變,SM2=0不用接收到有效停止位才RI=1,     //REN=1允許接收     TMOD = 0x21; //定時器1 定時方式2(8位),定時器0 定時方式1(16位)     TCON = 0x40; //設定時器1 允許開始計時(IT1=1)     TH1 = 0xfD;  //FB 18.432MHz 9600 波特率     TL1 = 0xfD;  //fd 11.0592 9600     IE = 0X90;     //EA=ES=1     TR1 = 1;     //啟動定時器     WDT_CONTR = 0x3c;//使能看門狗     p_U2270B_Standby = 0;//單電源     PCON = 0x00;    IP = 0x10;//uart you xian XXXPS PT1 PX1 PT0 PX0     led_light1 = 1;    led_light = 0;    p_U2270B_OutPut = 1;    }    /************************************************/    void f_readcard()//讀卡     {    EA = 0;//全關,防止影響跳變的定時器計時     WDT_CONTR = 0X3C;//喂狗     p_U2270B_CFE = 1;//      delay_2(232);  //>2.5ms            /*   //   aor    用喚醒功能來防碰撞   p_U2270B_CFE = 0; delay_2(18);//start gap>150us   write_bit(1);//10=操作碼讀0頁   write_bit(0);       write_password(&bankdata[24]);//密碼block7   p_U2270B_CFE =1 ;//    delay_2(516);//編程及確認時間5.6ms   */    WDT_CONTR = 0X3C;//喂狗     led_light = 0;    b.W = 0;    while(!(read_ok == 1))    {             //while(p_U2270B_OutPut);//等一個穩定的低電平?超時判斷?              while(!p_U2270B_OutPut);//等待上升沿的到來同步信號檢測1       TR0 = 1;      //deng xia jiang       while(p_U2270B_OutPut);//等待下降沿       TR0 = 0;   a.B.H = TH0;   a.B.L = TL0;   TH0 = TL0 = 0;   TR0 = 1;//定時器晚啟動10個周期       //同步頭       if((324 < a.W) && (a.W < 353)) ;//檢測同步信號1                  else     {     TR0 = 0;     TH0 = TL0 = 0;     goto read_error;    }      //等待上升沿        while(!p_U2270B_OutPut);   TR0 = 0;   a.B.H = TH0;   a.B.L = TL0;   TH0 = TL0 = 0;   TR0 = 1;//b.N1<<=8;            if(a.B.L < 195);//0.5p       else     {     TR0 = 0;     TH0 = TL0 = 0;     goto read_error;    }      //讀0~7塊的數據       for(j = 0;j < 28;j++)      {       //uchar i;                  for(i = 0;i < 16;i++)//8個位        {        //等待下降沿的到來         while(p_U2270B_OutPut);                TR0 = 0;     a.B.H = TH0;     a.B.L = TL0;     TH0 = TL0 = 0;     TR0 = 1;              if(t2_max < a.W/*)&&(a.W < t2_max)*/)//1P          {         b.W >>= 2;//先左移再賦值          b.B.L += 0xc0;                             i++;        }        else if(t1_min < a.B.L/*)&&(a.B.L < t1_max)*/)//0.5p         {         b.W >>= 1;         b.B.L += 0x80;                           }        else      {      TR0 = 0;      TH0 = TL0 = 0;      goto read_error;     }        i++;        while(!p_U2270B_OutPut);//上升                   TR0 = 0;     a.B.H = TH0;     a.B.L = TL0;     TH0 = TL0 = 0;     TR0 = 1;                      if(t2_min < a.W/*)&&(a.W < t2_max)*/)//1P          {         b.W >>= 2;         i++;        }        else if(t1_min < a.B.L/*a.W)&&(a.B.L < t1_max)*/)//0.5P         //else if(!(a.W==0))         {         b.W >>= 1;         //temp+=0x00;          //led_light1=0;led_light=1;delay_2(40000);         }        else      {      TR0 = 0;      TH0 = TL0 = 0;      goto read_error;     }        i++;       }       //取出奇位        DATA = b.B.L;       BIT13 = BIT7;    BIT12 = BIT5;    BIT11 = BIT3;    BIT10 = BIT1;       DATA = b.B.H;       BIT17 = BIT7;    BIT16 = BIT5;    BIT15 = BIT3;    BIT14 = BIT1;       bankdata[j] = DATA1;      }              read_ok = 1;//讀卡完成了     read_error:    _nop_();    }       }    /***************************************************/    void f_writecard(uchar x)//寫卡     {    p_U2270B_CFE = 1;    delay_2(232);  //>2.5ms            //psw=0 standard write     if (x == write_command0)//寫密碼:初始化密碼     {      uchar i;      uchar data *data p;      p = cominceptbuff;      p_U2270B_CFE = 0;   delay_2(31);//start gap>330us       write_bit(1);//寫操作碼1:10       write_bit(0);//寫操作碼0       write_bit(0);//寫鎖定位0       for(i = 0;i < 35;i++)      {       write_bit(1);//寫數據位1       }      p_U2270B_CFE = 1;      led_light1 = 0;   led_light = 1;   delay_2(40000);//測試使用       //write_block(cominceptbuff[4],p);       p_U2270B_CFE = 1;      bankdata[20] = cominceptbuff[0];//密碼存入       bankdata[21] = cominceptbuff[1];      bankdata[22] = cominceptbuff[2];      bankdata[23] = cominceptbuff[3];    }    else if (x == write_command1)//配置卡參數:初始化     {      uchar data *data p;      p = cominceptbuff;      write_bit(1);//寫操作碼1:10       write_bit(0);//寫操作碼0       write_bit(0);//寫鎖定位0               write_block(cominceptbuff[4],p);      p_U2270B_CFE=  1;    }    //psw=1  pssword mode     else if(x == write_command2)  //密碼寫數據    {      uchar data*data p;      p = &bankdata[24];      write_bit(1);//寫操作碼1:10       write_bit(0);//寫操作碼0       write_password(p);//發口令       write_bit(0);//寫鎖定位0       p = cominceptbuff;      write_block(cominceptbuff[4],p);//寫數據            }    else if(x == write_command3)//aor    //喚醒 {      //cominceptbuff[1]操作碼10 X xxxxxB       uchar data *data p;      p = cominceptbuff;      write_bit(1);//10       write_bit(0);             write_password(p);//密碼       p_U2270B_CFE = 1;//此時數據不停的循環傳出     }    else //停止操作碼     {      write_bit(1);//11       write_bit(1);             p_U2270B_CFE = 1;         }    p_U2270B_CFE = 1;    delay_2(560);//5.6ms     }    /************************************/    void f_clearpassword()//清除密碼     {    uchar data *data p;    uchar i,x;          p = &bankdata[24];//原密碼     p_U2270B_CFE = 0; delay_2(18);//start gap>150us     //操作碼10:10xxxxxxB     write_bit(1);    write_bit(0);              for(x = 0;x < 4;x++)//發原密碼     {             DATA = *(p++);      for(i = 0;i < 8;i++)      {       write_bit(BIT0);       DATA >>= 1;      }    }    write_bit(0);//鎖定位0:0     p = &cominceptbuff[0];    write_block(0x00,p);//寫新配置參數:pwd=0             //密碼無效:即清除密碼     DATA = 0x00;//停止操作碼00000000B     for(i = 0;i < 2;i++)    {    write_bit(BIT7);    DATA <<= 1;    }    p_U2270B_CFE = 1;       delay_2(560);//5.6ms     }    /*********************************/    void f_changepassword()//修改密碼            {       uchar data *data p;    uchar i,x,addr;    addr = 0x07;//block7     p = &Nkey_a[0];//原密碼     DATA = 0x80;//操作碼10:10xxxxxxB     for(i = 0;i < 2;i++)    {      write_bit(BIT7);      DATA <<= 1;    }    for(x = 0;x < 4;x++)//發原密碼     {             DATA = *(p++);      for(i = 0;i < 8;i++)      {       write_bit(BIT7);       DATA >>= 1;      }    }    write_bit(0);//鎖定位0:0     p = &cominceptbuff[0];    write_block(0x07,p);//寫新密碼     p_U2270B_CFE = 1;    bankdata[24] = cominceptbuff[0];//密碼存入     bankdata[25] = cominceptbuff[1];    bankdata[26] = cominceptbuff[2];    bankdata[27] = cominceptbuff[3];    DATA = 0x00;//停止操作碼00000000B     for(i = 0;i < 2;i++)    {      write_bit(BIT7);      DATA <<= 1;    }    p_U2270B_CFE = 1;       delay_2(560);//5.6ms     }    /***************************子函數***********************************/    void write_bit(bit x)//寫一位     {    if(x)    {      p_U2270B_CFE = 1;   delay_2(32);//448*11.0592/120=42延時448us       p_U2270B_CFE = 0;   delay_2(28);//280*11.0592/120=26寫1     }    else    {      p_U2270B_CFE = 1;   delay_2(92);//192*11.0592/120=18       p_U2270B_CFE = 0;   delay_2(28);//280*11.0592/120=26寫0     }    }    /*******************寫一個block*******************/    void write_block(uchar addr,uchar data *data p)    {    uchar i,j;        for(i = 0;i < 4;i++)//block0數據     {             DATA = *(p++);      for(j = 0;j < 8;j++)      {       write_bit(BIT0);       DATA >>= 1;      }    }    DATA = addr <<= 5;//0地址     for(i = 0;i < 3;i++)    {      write_bit(BIT7);      DATA <<= 1;    }                   }    /*************************************************/    void write_password(uchar data *data p)    {    uchar i,j;        for(i = 0;i < 4;i++)//     {             DATA = *(p++);      for(j = 0;j < 8;j++)      {       write_bit(BIT0);       DATA >>= 1;      }    }        }   /*************************************************/   void main()    {    initial();    TI = RI = 0;    ES = 1;    EA = 1;  delay_2(28);   //f_readcard();     while(1) {   f_readcard();      //讀卡   f_writecard(command1);  //寫卡    f_clearpassword();   //清除密碼     f_changepassword();    //修改密碼 } }

    標簽: 12345

    上傳時間: 2017-10-20

    上傳用戶:my_lcs

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